Quick Question - Conservation of Momentum

Click For Summary
SUMMARY

The discussion centers on the conservation of momentum, specifically analyzing a ball with a mass of 0.10 kg and initial velocity of 7 m/s that strikes a concrete wall and rebounds at 4 m/s. The change in momentum is calculated as the difference between the initial and final momentum. The correct answer to the change in momentum is 1.1 kg m/s, derived from the formula: change in momentum = final momentum - initial momentum.

PREREQUISITES
  • Understanding of momentum calculation
  • Basic knowledge of physics principles
  • Familiarity with mass and velocity concepts
  • Ability to perform simple arithmetic operations
NEXT STEPS
  • Study the principles of conservation of momentum in elastic and inelastic collisions
  • Learn about momentum calculations in two-dimensional collisions
  • Explore real-world applications of momentum in sports physics
  • Investigate the effects of mass and velocity on momentum changes
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and its applications in real-world scenarios.

Dooga Blackrazor
Messages
258
Reaction score
0
ball with a mass of 0.10 kg has a velocity of 7 m/s. It strikes a concrete wall perpendicularly and bounces straight back with velocity of 4 m/s. The change in the ball's momentum was equal to

Response Answer Choices
a. 0.30 kg m/s
b. 0.10 kg m/s
c. 0.40 kg m/s
d. 1.1 kg m/s

0.1 x 7 and .4 x .1 = .7 and .4 and subtracting them gives .30 kg m/s, correct?
 
Physics news on Phys.org
Nevermind, I found the answer (1.1). Silly mistake.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
10
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
1K
Replies
10
Views
3K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K