View Full Version : what is the limit of ......
thomate1
Oct4-05, 01:47 AM
I am a physics student. While I was doing problem concerned with moment of inertia, I got stuck at a point. I got the moment of inertia of a material line as
lim a -> 0 (3ab)/(a^3 + b^3)
What is the limit?
Thanks in advance for your help
The limit for the expression you've written is zero, provided b does not equal zero.
HallsofIvy
Oct5-05, 12:21 PM
And if b= 0, 3ab/(a^3+b^3)= 0 for all a so the limit is still 0!
thomate1
Oct6-05, 04:37 AM
I am sorry that the question I posed was not what I supposed. I meant
lim a->0 (a^3 + b^3)/(3ab)
Thanks in advance for your help
It looks like the lim = 0, since a = 0.
Man its been a while since i did this stuff.
VietDao29
Oct6-05, 11:47 AM
Nope. The limit does not exist here.
Since b is in the denominator, so b \neq 0
So
\lim_{a \rightarrow 0} \frac{a ^ 3 + b ^ 3}{3ab}
The numerator will tend to b3, while the denominator will tend to 0. So the limit does not exist.
Viet Dao,
So the limit does not exist.
Does that mean there is an asymptote there or something?
VietDao29
Oct6-05, 11:59 AM
Does that mean there is an asymptote there or something?
Yup, there's a vertical asymptote there.
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