Proving Non-Empty Compact Sets in n-Dimensional Space

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The discussion centers on proving that the intersection of an infinite sequence of non-empty compact sets \( C_k \) in \( \mathbb{R}^n \), where \( C_{k+1} \subset C_k \) for all \( k \), is also non-empty. The key argument involves utilizing the properties of compact sets, specifically the finite intersection property, and the relationship between compact sets and their complements. The participants emphasize the importance of compactness in ensuring that the intersection remains non-empty despite the infinite nature of the sets involved.

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Any help will be very gracious.

If [tex]\text C_{1} , C_{2} , C_{3}[/tex] are all non empty compact sets in [tex]\text R^n[/tex] such that [tex]\text C_{k+1} \subset C_{k}[/tex] for all k=1,2,3,..., then the set [tex]\text C = I_{k=1}^{\infty}C_{k}[/tex] is also non-empty.
 
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The basic problem is that there are an infinite number of [itex]C_n[/itex] involved. You should already know how to deal with unions of infinite numbers of open sets. So try looking at the complements of [itex]C_n[/itex].

Carl
 
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The complement of a closed set is open and of course all compact sets are closed. But it is crucial that these sets be compact and don't see how looking at their complements will include that.

If you were allowed to use the "Finite Intersection Propery"- If the intersection of any finite subset of a collection of compact sets is non-empty, then the intersection of all of them is non-empty- this would be trivial. However, I suspect that the whole point of this is to prove a relatively simple version of that.

Try this: Let {Uα} be an open cover for C1. Then, since every Cn is a subset of C1, it is also an open cover for Cn. Since each Cn is a compact, there exist a finite sub-cover.
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