Load on ladder leaning against a wall

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Homework Help Overview

The problem involves a ladder leaning against a smooth wall at a specific angle, with a load applied at a certain position along the ladder. The objective is to determine the reaction force between the ladder and the ground while considering the equilibrium of the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equilibrium conditions, including forces in both the x and y directions, as well as torque considerations. There is a focus on defining the reaction force and its implications for solving the problem. Some participants question the necessity of knowing the ladder's length for calculating moments.

Discussion Status

The discussion has seen various approaches to resolving the problem, with some participants offering guidance on using moments and others questioning the assumptions made about the ladder's length. There is an acknowledgment of different interpretations of the reaction force, but no explicit consensus has been reached.

Contextual Notes

Participants note the absence of the ladder's length in the problem statement, which affects the ability to calculate moments. The discussion reflects on the definitions of forces involved and the conditions of equilibrium required for the analysis.

engcon
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Hello, I got this problem from a book

"A light ladder leans against a perfetly smooth vertical wall at an angle of 30 degrees to the horizontal. A load of 800N is placed 3-quarters of the way up the ladder. If the ladder rests on a rough horizontal surface which prevents slipping, find the magnitude and direction of the reaction between the ladder and the ground"

Since the system is in equilibrium, I resolved vertically and got

R sin(theta) = 800

where R is the reaction force, and theta is the angle of the reaction force with the horizontal.

The problem is I can't get another equation so that I can find R and theta.

Any help is appreciated, thanks!
 
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Okay, first of all, my definition of "reaction" is the normal force produced by any surface, which I think does not coincide with your definition. In anycase, This problem involves three equations which are easily solved.

1. Fnet = 0 (in the x direction)
2. Fnet = 0 (in the y direction)
3. Mnet = 0 (torque, no rotation)

The frictionless wall will only produce a force in x. The floor will only produce a force in y. The friction at ladder's base will produce a force in -x. The 800 N load will produce a force in the -y.

Now for moments. Take the moments about the ladder's base (you can choose any point, but this point is particularly easy. Then the two forces that will create a torque around this point will be the 800N load (counter clockwise) and the reaction force of the wall (clockwise). They must sum up to zero.

Go get em =)
 
mezarashi said:
Now for moments. Take the moments about the ladder's base (you can choose any point, but this point is particularly easy. Then the two forces that will create a torque around this point will be the 800N load (counter clockwise) and the reaction force of the wall (clockwise). They must sum up to zero.

Go get em =)

No mention of the ladder length is made, so I cannot use moments
 
engcon said:
No mention of the ladder length is made, so I cannot use moments

Are you sure? Try denoting the length of the ladder as L. Leave it as L (you don't need to substitute a number), and see what happens.
 
Solved

Did that, and solved it

Thanks
 

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