Superman Holding the Moon: Is It an Impressive Feat?

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Discussion Overview

The discussion revolves around the feasibility and implications of Superman holding the Moon, particularly in the context of physics and the forces involved. Participants explore the concepts of momentum, force, and the mass of the Moon, while referencing comic book scenarios and real-world physics principles.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the impressiveness of Superman's feat, asking how much force would be needed to hold the Moon stationary against a specified acceleration of 0.5G.
  • Another participant clarifies that momentum is not measured in units of force or acceleration, suggesting that the force required to prevent the Moon from accelerating would equal the force needed to accelerate it at 0.5G.
  • A participant provides a calculation indicating that the force required to accelerate the Moon at 0.5G would be equivalent to holding up an extraordinarily large weight on Earth.
  • Further calculations are presented regarding the mass of the Moon and its weight under different gravitational conditions, with one participant estimating the weight under a very small fraction of G-force.
  • Another participant humorously speculates about the implications of Superman's actions on the Moon's structure and composition, suggesting that he might push through the Moon if he exerted enough force.

Areas of Agreement / Disagreement

Participants express differing views on the clarity of the original question and the implications of the forces involved. There is no consensus on the impressiveness of Superman's feat or the exact calculations related to the forces at play.

Contextual Notes

Some participants express uncertainty regarding the definitions of momentum and force, and there are unresolved questions about the implications of varying fractions of G-force in the context of Superman's abilities.

randy23
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I'm a comic fan especially Superman and one of his feats dealt with him holding the moon that was supposedly increasing in momentum at fraction of a G-Force. My question is: is that really an impressive feat? A fraction of a G-Force? If it was half of a G-Force, how much force would he holding back against the moon to keep it stationary?
 
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The question isn't too clear, momentum isn't measured in units of force or acceleration...are you saying that if Superman wasn't pushing back, the moon would be accelerating at 0.5G? Because the moon is so massive, the force needed to get it to accelerate like that would be pretty huge (just multiply the moon's mass by an acceleration of 0.5G), and the force needed to push back and prevent the moon from accelerating would need to be the same size.
 
JesseM said:
The question isn't too clear, momentum isn't measured in units of force or acceleration...are you saying that if Superman wasn't pushing back, the moon would be accelerating at 0.5G? Because the moon is so massive, the force needed to get it to accelerate like that would be pretty huge (just multiply the moon's mass by an acceleration of 0.5G), and the force needed to push back and prevent the moon from accelerating would need to be the same size.

Well I'm not sure about the momentum. DC is pretty much based on pseudo-science but I just wanted to know using real sciences. Thank you for the insightful reply.
 
For some numbers, the amount of force needed to accelerate the Moon at .5g would be about the same as what it would take to hold up a 80,000,000,000,000,000,000,000 lb weight on the surface of the Earth.
 
Janus, thanks for the calculations. How did you go about calculating that number?
 
The Moon has A mass of 7.35 x 1022 Kilograms
A mass of one kilogram weighs 2.2 lbs on the surface of the Earth at 1g.
The same kilogram would weigh half as much at 0.5g or 1.1lb.
1.1lb/kg x 7.35 x 1022 kg = 8 x 1022lbs
 
Thanks. But the fraction of g-force they commented about could also mean .000000001, right?
 
randy23 said:
Thanks. But the fraction of g-force they commented about could also mean .000000001, right?

Okay, then the weight would be 160,000,000,000,000 lbs. (about equal to the weight of 10 billion African Bull elephants)
 
Why would Superman want to tinker with the Moon? It's fine where it is.
If Superman were pushing hard enough on the Moon for it to have any significant impact, he would probably push through the Moon instead. If 10 billion African Bull elephants had their mass compacted into the size of Superman I doubt the surface of the Moon could support it. Superman would quickly find himself at the core of the Moon. But that would be cool because he could tell us what it is made of. I know the surface is Swiss, but I believe scientists theorize that the core is Cheddar.
 

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