Solve Power Problem of Grandfather Clock

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SUMMARY

The power delivered by a grandfather clock, powered by a 4.00 kg weight descending 0.750 m over 3.00 days, is calculated using the formula P = W/t. The work done (W) is derived from the force (F) multiplied by the distance (d), where F is determined by the mass (m) and acceleration (a). The correct acceleration due to gravity (9.81 m/s²) must be used instead of the incorrect value of 1.116x10^-11. The final power output is calculated as P = 1.292x10^-16 watts, indicating a need for reevaluation of the force acting on the clock.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m*a)
  • Knowledge of work and energy concepts (W = F*d)
  • Familiarity with power calculations (P = W/t)
  • Basic grasp of gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Review the principles of gravitational force and its application in mechanical systems.
  • Learn about energy conservation in mechanical systems, particularly in pendulum clocks.
  • Investigate the effects of friction and air resistance on mechanical power calculations.
  • Explore advanced power calculation techniques in physics, including the use of calculus for variable forces.
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Physics students, mechanical engineers, and hobbyists interested in the mechanics of clockwork systems and power calculations.

SoccaCrazy24
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A grandfather clock is powered by the descent of a 4.00 kg weight.
If the weight descends through a distance of 0.750 m in 3.00 days, how much power does it deliver to the clock?
I used my equations...
P=W/t
W=F*d
therefore P = (F*d)/t
F=m*a
m=4.00 kg
a=1.116x10^-11 ?
therefore F=4.465x10^-11 ?
d=.75 meters
t=259200 seconds
P= 1.292x10^-16 ?
This is obviously not right to me... but on the force i know its net but where along the way do i find the net force accting upon the clock... if i can figure out F in the equation then i will have the answer... help...
 
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Where did you get that value for a? The rest is great, but you should rethink what is accelerating the 4kg weight.
 

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