Finding Aphelion Distance After Satellite Explosion

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SUMMARY

The discussion focuses on calculating the aphelion distance of a satellite after it explodes into two fragments, one of mass 4m and another of mass m. Initially, the velocity of the satellite in a circular orbit is derived using the formula for circular motion, leading to a time period calculation. Post-explosion, the fragment of mass m becomes stationary, while the mass 4m's velocity is determined using conservation of momentum, yielding an instantaneous velocity of 5/4 sqrt(GM/r). The final goal is to find the aphelion distance, which is confirmed to be (25/7)r, with the perihelion being the radius r at the moment of explosion.

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Kenny Lee
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Hi, how does one go about finding the aphelion distance when all the information you've got is the satellite's velocity at one point in time?? Here's the Q:
1) first you're to find an expression for the velocity of a satellite in circular orbit about planet of mass M. The orbit radius = r. Simple enough
2) then you find its time period - simple enough
3) then it says, the satellite explodes; breaking into two pieces. One of mass 4m and another of mass m. The mass m becomes stationary with respect to the Earth (i.e. v=0). Find the instantaneous v of mass 4m now - consv of momentum Q. Simple enough.
(Answer btw is 5/4 sqrt. (GM/r)--- for next Q. )
This is where i get lost.
4) it says that the broken satellite of mass 4m, because of increase in speed, now undergoes elliptical motion. We're supposed to find its distance away from the center of the Earth when it reaches the other end of the ellipse.
Answer's (25/7)r
Now I presume its talking about the aphelion distance. Cause at the instance of explosion its going to be at radius r, and again I'm guessing that that's the perihelion. So the 'other end' could be the aphelion? Regardless, I just don't know how to get about the Q. Help me out pls.
 
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HINT: Both the energy and angular momentum of the fragment will be conserved.
 
Yea? I'll give it a try.
 

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