Circular Motion: Centripetal Force Comparison Between Andy and Bella

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SUMMARY

In the discussion regarding centripetal force experienced by Andy and Bella, it is established that both individuals move with the same angular velocity (\omega), but their masses and distances from the center differ. Andy's mass is denoted as m_a, while Bella's mass is m_b, which is half of Andy's. The distances from the center are R_a for Andy and R_b for Bella, with R_a being twice R_b. The calculated centripetal forces reveal that Andy experiences a force four times greater than Bella, contradicting the initial assertion that both forces are equal.

PREREQUISITES
  • Understanding of centripetal force formula: F_c = m\omega^2R
  • Knowledge of angular velocity and its implications in circular motion
  • Familiarity with mass and distance relationships in physics
  • Ability to manipulate ratios and algebraic expressions
NEXT STEPS
  • Study the derivation of centripetal force in circular motion scenarios
  • Explore the implications of mass and radius on centripetal acceleration
  • Learn about angular velocity and its role in dynamics of circular motion
  • Investigate common misconceptions in physics problems related to forces
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of circular motion and centripetal force calculations.

dekoi
Andy and Bella move in circular paths about a common point with the same constant angular velocity [tex]\omega[/tex]. Bella's mass is half the mass of Andy. The distance, where Andy is from the centre of the circle, is twice the distance of Bella. Who of the two will experience the greater magnitude of the centripetal force, [tex]F_c[/tex]?

The answer given is that they will experience the SAME force. However, I found otherwise.

Since [tex]F_c=m\omega^2R[/tex]

[tex]F_a=m_a\omega^2R_a[/tex] and [tex]F_b=m_b\omega^2R_b[/tex]

The ratios I obtained were: [tex]m_b=\frac{m_a}{2}[/tex] and [tex]R_b=\frac{R_a}{2}[/tex].

When I find the ratio, I get:
[tex]\frac{F_a}{F_b}=\frac{m_a\omega^2R_a}{m_b\omega^2R_b}=\frac{m_aR_a}{\frac{m_a}{2}\frac{R_a}{2}}[/tex]

My end result will be the value, 4, which is not 1, which I am looking for in order for the forces to be equal.

Is there a problem with my method, or is the answer given the wrong answer?
 
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I agree with your analysis. The answer is wrong. (Or someone messed up the problem statement.)
 
Thank you.
 

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