View Full Version : Quick Physics Help....
Inquiring_Mike
Nov24-03, 02:43 PM
X and Z represent point charges of -2.4 x 10^-3 C and +3.3 x 10^-2 C respectively. Calculate the magnitude and direction of the electric field intensity at point Y, 5.00 cm from X and 8.50 cm from Z (they all live in a line).
Can sumone help me?
himanshu121
Nov24-03, 02:46 PM
Apply the superposition principle i.e Electric field at point will be equal to electic field due to X + due to Z.
Inquiring_Mike
Nov24-03, 02:52 PM
So does 4.974 x 10^10 look good?
himanshu121
Nov24-03, 03:02 PM
you didn't tell about the location of point ,is it left of X or right of Z or in between which will decide mag+dir
Inquiring_Mike
Nov24-03, 03:09 PM
X -----5.0------- Y----------8.5--------Z
himanshu121
Nov24-03, 03:19 PM
direction will be towards YX and magnitude=9x10^9(2.4x10^-3/5x 10^-2+ 3.3 x 10^-2/ 8.5x10^-2
=3.92 x 10^9
Inquiring_Mike
Nov24-03, 04:09 PM
Ah...... It all makes sense now.....
THanks for the help!
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