Velocity of mail bag released from helicopter

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The discussion focuses on the physics of a mail bag released from a helicopter ascending at a constant speed of 1.5 m/s. Using the equation Vf = Vi + a*t, where the acceleration due to gravity (a) is 9.8 m/s², the final velocity (Vf) of the mail bag after 2 seconds is calculated to be 21.1 m/s. Additionally, the height of the mail bag after 2 seconds is determined to be 57.8 m, given that the helicopter starts at a height of 100 m.

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A small mail bag is released from a helicopter. The helicopter is rising with a constant speed of 1.5 m/s

After 2.0 seconds, what is the VELOCITY of the mailbag?
I use the equation Vf = Vi + a*t
and a would be 9.8 m/s squared right?
 
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yes 9.8 is correct

so what is the vel after 2 sec.

if the helicopter is at a height if 100 m what is the height of the bag after 2 secs
 
the velocity would be 21.1 m/s and the height of the bag would be 57.8 m ?
 

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