What is the electrostatic force between two atoms?

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Discussion Overview

The discussion revolves around the electrostatic force between two atoms, exploring the nature of attraction between neutral atoms and comparing it to gravitational forces. Participants examine the interactions of positive and negative charges within atoms and how these might relate to gravitational attraction.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Exploratory

Main Points Raised

  • One participant suggests that the electrostatic force can be calculated by considering the interactions of all positive and negative charges in two balls (atoms) and claims that gravity is a manifestation of electrostatic forces.
  • Another participant counters that the net charge of each ball is zero, leading to a conclusion that the electrostatic force is also zero, while gravitational force is determined by mass.
  • Some participants argue that even with zero net charge, the distances between positive and negative charges in atoms could result in a small electrostatic attraction, which they equate to gravity.
  • Others challenge this view, stating that the forces involved in atomic interactions do not yield gravitational forces and highlight the existence of gravitational fields in neutron stars, which lack charge.
  • There are claims that the mathematical similarities between gravitational and electrostatic forces do not imply they are the same phenomenon, and that the models used to describe them differ fundamentally.
  • A participant proposes a calculation involving forces between specific charges in atoms, suggesting that it results in an attraction that varies with mass and distance.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the nature of forces between atoms, with no consensus reached on the relationship between electrostatic and gravitational forces. Disagreements persist about the validity of claims regarding attraction between neutral atoms and the implications of charge distributions.

Contextual Notes

Some claims rely on assumptions about charge distributions and interactions that are not universally accepted. The discussion also touches on the limitations of models used to describe forces, particularly in the context of neutral atoms and gravitational interactions.

hello1
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We put ball A and ball B by distance R, every atom in ball A has some positive charges and some negative charges, same as atoms in ball B.

Now suppose every positive charge in ball A attracts every negative charge and repells every positive charge in ball B, and verse visa.

Now we have all the single force add up, we find it equals to f=gxm1xm2/rxr

I once did some calculation, it sounds looked right, but now I forgot the details.

So, I believe, gravity is the shadow of electrostatic force.

An easier way to see this is to put two atoms apart and calculate the forces between all positive and negative charges.

You may find I was right. If not, please let me know why, be appreciate.
 
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hello1 said:
We put ball A and ball B by distance R, every atom in ball A has some positive charges and some negative charges, same as atoms in ball B.
OK, but realize that the net charge on each ball is zero.
Now suppose every positive charge in ball A attracts every negative charge and repells every positive charge in ball B, and verse visa.
That's exactly what happens.
Now we have all the single force add up, we find it equals to f=gxm1xm2/rxr
Nope. The electrostatic force is zero. On the other hand, the gravitational force, which is associated with mass not charge, is given by Newton's law of gravity.
 
hello1 said:
...
I once did some calculation, it sounds looked right, but now I forgot the details.

sounds looked like a crank turning to me.
 
Why is an atom attracts another atom? They are both zero net charged.

My point is even in every atom the net charge is zero, but the distance between positive charge and negative change between two atoms will smaller than same charges.

The net force end up a mighty small percentage of the electrcostatic attration force. This is what we called gravity.
 
And the point of everyone who has answered is that you are wrong. Very delicate have been done to determine precisely the force given by the difference in distances you are talking about- they do not give anything like the gravitational force. It is also well known that "neutron stars"- which have NO positive or negative charges at all- have strong gravitational fields.
 
hello1 said:
Why is an atom attracts another atom? They are both zero net charged.
My point is even in every atom the net charge is zero, but the distance between positive charge and negative change between two atoms will smaller than same charges.
The net force end up a mighty small percentage of the electrcostatic attration force. This is what we called gravity.
Do you mean that oppisite charges will be pulled together?
That also won't cause an attraction, cause an equal amount of + and - charges will be pulled from each atom, so for example, a + charge in mass1 pulls a - charge from mass2 closer to it, but at the same time a + from mass2 is being pulled by a - in mass 1...
 
hello1 said:
Why is an atom attracts another atom? They are both zero net charged.
My point is even in every atom the net charge is zero, but the distance between positive charge and negative change between two atoms will smaller than same charges.
The net force end up a mighty small percentage of the electrcostatic attration force. This is what we called gravity.

Where EXACTLY does another attom "attracts" another atom? In molecules? In solids? Have you studied what happens there? Have you heard of orbital HYBRIDIZATION? Have you looked at what KINDS of atoms that can form such a thing? Have you studied orbital bonding and why certain atoms can form such bonds while others can't?

No?

Well you SHOULD, at least BEFORE you put forward such outlandish speculation. You may also want to re-read the PF Guildlines on speculative posting before you proceed any further.

Zz.
 
hello1 said:
Why is an atom attracts another atom? They are both zero net charged.
Well... because your idea is wrong. It isn't magnetism, it's gravity.
My point is even in every atom the net charge is zero, but the distance between positive charge and negative change between two atoms will smaller than same charges.
The net force end up a mighty small percentage of the electrcostatic attration force. This is what we called gravity.
Nope. Still wrong. An object that has all it's magnetic poles aligned in such a way as to not have a balanced (note: unbalanced doesn't mean it isn't still zero) charge is a magnet. Magnets don't behave anywhere near the way objects in gravity behave.
 
Why is gravity has the same nature as electical force? Is any other force has the form of f=c m1m2/rr?
 
  • #10
hello1 said:
Why is gravity has the same nature as electical force? Is any other force has the form of f=c m1m2/rr?

That isn't a good enough reason! There are MANY instances in physics where the mathematical forms are similar. Doesn't mean they are all the same phenomena sharing the same mechanism! If this is your only argument for your "theory", you have a lot of holes to plug.

Furthermore, electric fields are not the result of ANY "shielding" of anything. Yet, this is how you are modelling your gravitational interaction. So in your model, gravity and electric field are of a DIFFERENT nature. So it is YOU who has to account for why they have the same dependence on distance!

I'm guessing you realize why your argument on why neutral atoms "attract" one another is no longer valid.

Zz.
 
  • #11
Let's see this way. Calculate the force between one atom in ball A and another in ball B.

Suppose the sample atom has p3 and e1, e2, e3 chagres, it is nutraul. The distance between the center of the two atoms is r, it is much larger than the dr which is the radin of the atom, then we have F=fp3e1+fp3e2+fp3e3+fp3e1+fp3e2+fp3e3-fp3p3-fe1e1-fe1e2-fe1e3-fe2e1-fe2e2-fe2e3-fe3e1-fe3e2-fe3e3.

It end up an attraction force, it increases with the mass (total charge) and decreases with distance square.
 
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  • #12
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hello1 said:
Let's see this way. Calculate the force between one atom in ball A and another in ball B.
Suppose the sample atom has p3 and e1, e2, e3 chagres, it is nutraul. The distance between the center of the two atoms is r, it is much larger than the dr which is the radin of the atom, then we have F=fp3e1+fp3e2+fp3e3+fp3e1+fp3e2+fp3e3-fp3p3-fe1e1-fe1e2-fe1e3-fe2e1-fe2e2-fe2e3-fe3e1-fe3e2-fe3e3.
 

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