Finding Equal Force Distance from Moon

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Homework Help Overview

The original poster attempts to determine the distance from the moon where the gravitational forces from the Earth and the Sun on a particle are equal. The problem involves gravitational forces and distances in the context of celestial mechanics.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the expression derived by the original poster and question the validity of the mass variables used in the gravitational force equation. There is a focus on the distinction between the masses of the Earth, Moon, and the particle in question.

Discussion Status

Some participants have provided guidance on the correct interpretation of the mass variables in the gravitational equation. The discussion has revealed a misunderstanding regarding the masses involved, but no consensus has been reached on the correct expression yet.

Contextual Notes

The original poster appears to have overlooked the mass of the particle at the Lagrange point, which is relevant to the problem setup.

sony
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So I am supposed to find the distance from the moon where the force on a particle from the Earth and sun is equal.

I get this expression (earth-moon distance is 400 000km):
yMm/(r^2) = yMm / (400000km-r)^2

But from that I get r=200 000km and the answer should be 40 000km...

whats wrong with the expression?

thanks
 
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mass of the moon != mass of the earth
 
but the product of the masses is the same on both sides right? don't they cancel...?
 
No, they are not the same and they can't cancel if they are not the same.
 
then what is the expression...?
 
There should be only one mass variable on each side of your equation.
 
but Newtons gravitation law is yMm/r^2...
 
Yes. But do you KNOW what M and m are?
 
M=mass of earth
m=mass of moon

?
 
  • #10
oh, heh, I don't know what caused me to be so slow... I forgot the mass of the particle at the Lagrance point...

Bah, sorry for the trouble :P
 

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