Solving for Displacement on a 25° Incline w/ Kinetic Energy

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Homework Help Overview

The problem involves a monkey on a sled moving up a 25° incline with an initial speed of 3.5 m/s. The mass of the monkey and sled is 17.0 kg, and the coefficient of kinetic friction is 0.20. Participants are exploring how to determine the distance the sled travels up the incline before coming to a stop.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using kinematic equations and energy conservation methods to find displacement. Some express uncertainty about incorporating the incline angle and the effects of friction. Others mention drawing free body diagrams and calculating forces involved.

Discussion Status

There are various approaches being considered, including kinematic equations and energy methods. Some participants have provided specific equations and attempted calculations, while others have raised questions about the accuracy of the acceleration and the role of gravitational forces. No consensus has been reached on the correct method or answer.

Contextual Notes

Participants note the importance of considering friction and gravitational components in their calculations. There is also mention of a potential discrepancy in the calculated acceleration and its impact on the resulting displacement.

hshphyss
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Can anyone help me with this?

In a circus performance, a monkey on a sled is given an initial speed of 3.5 m/s up a 25° incline. The combined mass of the monkey and the sled is 17.0 kg, and the coefficient of kinetic friction between the sled and the incline is 0.20. How far up the incline does the sled move?

I tried using the kinematic equations to find out the displacement. But I was left without the time. I know that KE= .5 x mass x velocity^2 but that isn't going to help me find out the displacement. I was also unsure of where to incorporate the incline angle. Thank-you
 
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hshphyss said:
Can anyone help me with this?
In a circus performance, a monkey on a sled is given an initial speed of 3.5 m/s up a 25° incline. The combined mass of the monkey and the sled is 17.0 kg, and the coefficient of kinetic friction between the sled and the incline is 0.20. How far up the incline does the sled move?

I tried using the kinematic equations to find out the displacement. But I was left without the time. I know that KE= .5 x mass x velocity^2 but that isn't going to help me find out the displacement. I was also unsure of where to incorporate the incline angle. Thank-you
You have the initial velocity... 3.5m/s
friction co-eff... = 0.2
Ff = -0.2FN
You know that Fn is mgcos theta (Draw an FBD)
ma = - 0.2 mgcos 25
a = -0.2gcos25
To find displacement, use the formula:
v^2 = u^2 + 2as
And solve for s...
You have u, initial velocity, and v, final velocity. (= 0)
And a...
 
You can solve this problem using either the kinematic eqns or by energy conservation method.

Using the kinematic eqns, you could have used the eqn,
v² = u² - 2as
where v is the final velocity, u is the initial velocity, a is the deceleration, s is the distance travelled.
 
to the a= -1.78 and the equation would be
n 0^2=3.5^2+2(-1.78)x and it would come out to 3.45 but that answer is not correct when I enter into the answer checker
 
better not forget gravity!

knowing (or wanting to know) distances is a task for Work & Energy.
At the bottom, we have KE, while at the top we have PE_gravity.
The process has friction force (m g cos(theta)) doing negative Work.
Distance along the ramp is related to height uo the ramp by trig.
 
The acceleration is not 1.78 m/s^2. (Pseudo Statistic's answer ignored the component of weight acting down the incline.)
 

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