ࡱ > 5@ l bjbj22 " X X l 6 6 6 6 6 6 6 J 2 2 2 2 F J ^ $ R a x 6 6 6 \ \ \ 6 6 \ \ \ t 6 6 t R A8Q 2 t 0 t $ " t J J 6 6 6 6 6 t ( \ J J N F J J N Formula for surface area: EMBED Equation.3 My working: EMBED Equation.3 Now converting to cylindrical coordinates (and this is where it goes all wrong!): EMBED Equation.3 Im not exactly sure of the bounds for the integral, but below I have assumed that there are no restrictions on EMBED Equation.3 and that the radius of the disc (D) below the cone can go between 0 and R, as stated in the original question. EMBED Equation.3 From what I can see, this should be something like EMBED Equation.3 . I dont know if the EMBED Equation.3 in my answer represents the EMBED Equation.3 here, because it seems as though this would only occur where the angle between the x or y axis and the side of the cone, L was 45 degrees (say if H and R were both equal to 1). Still, I have come out with an R squared instead of an R. / 0 1 2 3 4 @ A B U V W X 5 6 I J K L uh j hz) ht\ EHUjqI ht\ PJ UVj ht\ Uht\ jR h R h R EHU!jnI h R CJ PJ UVaJ j` h R h R EHU!jtnI h R CJ PJ UVaJ h~Z j h R h R EHU!j+nI h R CJ PJ UVaJ j h R Uht\ h R >*h R " 3 4 @ A Y l l ! 7 8 K L M N j k ~ l ķٳ|o jW ht\ ht\ EHU!j^qI ht\ CJ PJ UVaJ j, ht\ ht\ EHU!jGqI ht\ CJ PJ UVaJ j ht\ Uht\ jg h R ht\ EHU!jpI ht\ CJ PJ UVaJ h R j h R Uj h R ht\ EH.U!jqI ht\ CJ PJ UVaJ 1h/ =!"#$% ` D d 4 b c $ A ? ? 3 " ` ? 2 C?w3H D `!~ C?w3Hr @ 0( p L xڥkAL&-ŊՃ$bszXTST =yK/= %ғ9!liJ]͛={d, `/͢Y,Xu.krOyCB,eog`K]3WZ7k(> 3GaX}1Q#4Jn:bTt|Xc砘\anŵ$jԵzm5 7Kn4_y4Vv|>^ϋ/yTjidgm3rR5< ȕ uI¸]ފtȠnUms1\mׁt]G$7{kعn*X@3D;?8'DVV*x}~z!͗l%AΈ{~$L=o?v7;G>$幏).(y9?WgPb|s\2|B#o'G`jZ /(z<bc?