|
|
|
complete the square
|
Definition/Summary
|
An expression (usually a quadratic) can often be simplified by adding a constant to it to make a perfect square.
This may make the solution of equations or of integrals much easier. |
|
Equations
|
QUADRATIC EQUATION:
[tex]x^2\ +\ 2bx\ =\ c[/tex]
complete the square by adding [itex]b^2[/itex] to both sides:
[tex](x+b)^2\ =\ b^2\ +\ c[/tex]
and so:
[tex]x+b\ =\pm\sqrt{b^2\ +\ c}[/tex]
or:
[tex]x\ =\ -b\ \pm\sqrt{b^2\ +\ c}[/tex]
FIND THE MINIMUM:
[tex]2(x-a)(x+\sqrt{x^{2}+b^{2}})[/tex]
complete the square once:
[tex]=\ (x-a)^2\ +\ x^2\ -\ a^2\ +\ 2(x-a)\sqrt{x^{2}+b^{2}}[/tex]
then complete the square again:
[tex]=\ (x-a)^2\ +\ 2(x-a)\sqrt{x^2+b^2}\ +\ (x^2+b^2)\ -\ a^2\ -\ b^2[/tex]
[tex]=\ \left(x\ -\ a\ +\ \sqrt{x^2+b^2}\right)^2\ -\ (a^2\ +\ b^2)[/tex]
so we now only need to find the minimum of [itex](x\ -\ a\ +\ \sqrt{x^2+b^2})^2[/itex]
INTEGRAL:
[tex]\int\frac{dx}{\sqrt{x^2\ +\ 2bx\ +\ c}}[/tex]
[tex]=\ \int\frac{dx}{\sqrt{(x+b)^2\ -\ b^2\ +\ c}}[/tex]
which is easy to solve by the substitution [itex]y \ =\ x+b[/itex] |
|
Recent forum threads on complete the square
|
|
|
|
|
Breakdown
|
|
Mathematics
> Algebra
>> Quadratic Forms
|
|
Commentary
|