Energy of a particle
A particle of mass 'm' is moving in a circular orbit under the influence of the potential [itex]V(x) = \frac{ar^4}{4}[/itex] where 'a' is a constant. Given that the allowed orbits are those whose circumference is [itex]n\lambda[/itex], where 'n' is an integer and [itex]\lambda[/itex] is the deBroglie wavelength of the particle. Obtain the energy of the particle as a function of 'n' and [itex]\lambda[/itex].
So, [tex]2\pi r_n = n\lambda[/tex] I don't understand how the potential of the orbit comes into the picture here. Isn't PE = 2KE for Bohr orbits? How is the energy calculated? 
Quote:
Dan 
Quote:

Quote:
Now, what is this is polar coordinates? Well, [tex]v^2=\dot{r^2}+r^2 \dot{\theta^2}[/tex] And, of course, E = T + V(r)... Dan BTW, you can get rid of the [tex]\dot{\theta}[/tex] by using angular momentum conservation. 
All times are GMT 5. The time now is 08:59 PM. 
Powered by vBulletin Copyright ©2000  2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums