Falling Water Droplet Homework: Show Radius & Speed Increase Linearly over Time

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SUMMARY

The discussion focuses on a physics homework problem regarding a water droplet falling through a humid atmosphere, where the droplet's mass increases proportionally to its cross-sectional area. The initial radius R0 is assumed to be negligible, allowing for the conclusion that both the radius and speed of the droplet increase linearly over time. The equation relating area to volume is provided as A = π[(4/3)π]^(-2/3) * Vol^(2/3). The solution involves solving a differential equation and applying momentum conservation principles.

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  • Basic geometry related to volume and area calculations.
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Homework Statement


Assume that a water droplet falling through a humid atmosphere gathers up mass at a rate that is proportional to its cross-sectional area A. Assumethat the droplet starts from rest and that its initial radius R0 is so small that it suffers no resistive force. Show that its radius adn its speed increase lineraly with time.


Homework Equations


A= pi[(4/3)pi]^(-2/3)*Vol^(2/3)


The Attempt at a Solution



I found the above equation to relate the area to the volume. I am stuck on this and do not know which direction I should head in.
 
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That's a poor question; it's forcing you to make a plainly unphysical assumption, namely that [itex]\dot{m}(t)=km^{2/3}(t)[/itex], when a much better assumption would be [itex]\dot{m}(t)=kv(t)m^{2/3}(t)[/itex]. However, the latter does not produce an easy answer, while the former does.

That said ... the above differential equation is trivially solved to give you the first answer that you need. For the second answer, you need to write an equation for momentum conservation and plug in the result from the first answer.
 
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