Distance actually travelled by a photon

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SUMMARY

The discussion centers on calculating the distance traveled by a photon between two galaxies, considering cosmic expansion. The key equation derived is the physical distance traveled by a light ray, expressed as lhor(t) = c * a(t) * ∫ dτ/a(τ), where a(t) is the scale factor. The user expresses frustration with the algebra involved and seeks guidance on how to manipulate the equations effectively. The integral is crucial for understanding the relationship between emitted and observed time intervals in cosmological contexts.

PREREQUISITES
  • Understanding of cosmological principles, specifically cosmic expansion.
  • Familiarity with the scale factor a(t) in cosmology.
  • Basic knowledge of calculus, particularly integration techniques.
  • Proficiency in algebraic manipulation of equations.
NEXT STEPS
  • Study the derivation of the scale factor a(t) in cosmological models.
  • Learn about the implications of the Friedmann equations on photon travel.
  • Explore the concept of comoving distance versus physical distance in cosmology.
  • Investigate the use of integrals in calculating distances in expanding universes.
USEFUL FOR

Astronomy students, physicists, and cosmologists interested in understanding the dynamics of light travel in an expanding universe.

vikter
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[SOLVED] Distance actually traveled by a photon

First I just want to say thanks to everyone on this site that take time to answer questions like mine. This is my first post but I've used the forum many times for help on other problems.

Homework Statement


Consider two observers separated by a fixed, comoving distance r (which we can set to be their distance today). The true physical distance between the galaxies of course changes with time due to cosmic expansion; for each small comoving distance increment dr, the corresponding increment in physical distance is just given by [tex]^{dl}phys[/tex] = a(t)dr.
Consider a light ray which moves from galaxy A to galaxy B. It's speed relative to the observers it passes is v = [tex]\frac{dl}{dt}[/tex] = a(t)dr/dt = c. Using this, show that a light ray emitted at time t = 0, and detected at time t, travels a physical distance
[tex]^{l}hor[/tex](t) = c * a(t) * [tex]\int d\tau/a(\tau)[/tex]. Sorry, that integral should be taken from 0 to t, but I'm not seeing how to add the code for that. And by this point I'm quite frustrated with not only the problem but trying to present it here in a coherent matter haha so I'm sorry if it's hard to follow. The actual version can be found http://www.astro.uiuc.edu/classes/astr406/ASSIGNMENTS/ps10.pdf starting at the bottom of the second to last page.

a(t) being the scale factor.

The attempt at a solution
I have about two pages worth of algebra etc which has led me nowhere so I'm not going to even bother. I understand the problem but really am quite lost as to how to get to where I need to go, so any suggestions will be GREATLY appreciated.

Thanks.
 
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update on my thinking

I'm trying to work with this equation: [tex]\Delta[/tex][tex]t_{obs}[/tex] = [tex]\Delta[/tex][tex]t_{em}[/tex] [tex]\frac{1}{a_e_m}[/tex]
 

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