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 Relena Jun26-08 01:51 PM

linear superconductor

For a super conductor there is a maximum current after which the energy of electrons will be higher than Fermi energy and no cooper pairs will exist .

Can this be evaded if we used linear superconductors rather than coils ?? thus, the motion of electron pairs could be inertial , And the cooper pairs wouldn't be destroyed.

Any Ideas?

 f95toli Jun26-08 03:14 PM

Re: linear superconductor

Linear? Coil?

The shape of the superconductor is not directly related to do with the maximum current it can carry (known as Jc); the maximum Jc in a given configuration is ultimately due to microscopic properties of the superconductor and is not a bulk propery as such.
Also, you can't really talk about a Fermi energy in this context (I suspect you mean the superconducting gap, but that is not the same thing as the Fermi energy). You can think of Jc as being determined by the critical magnetic field of the superconductor, it is the self-field generated by the current that is causing the Cooper pairs to break up.

(superconducting magnets the total field is of course due to the sum of the generated field+the self field; but this is not a problem in e.g. superconducting cables)

 Relena Jun27-08 02:17 AM

Re: linear superconductor

Quote:
 The shape of the superconductor is not directly related to do with the maximum current it can carry (known as Jc); the maximum Jc in a given configuration is ultimately due to microscopic properties of the superconductor and is not a bulk propery as such.
That's true of course , I saw that I missed the point , since electrons will always collide with atoms and lose energy after JC is reached .

thanks for your

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