Group cohomology problem
A group,G, contains a subgroup,Z, that is isomorphic to the integers.
Z is maximal in the sense that if for any g such that some power g^m is in Z then g is already in Z.
Is it true that any cohomology class ,h, in H^1(G;Z/2) that pulls back to the generator of H^1(Z;Z/2) via the inclusion homomorphism has trivial self-cup products? i.e. is h cup h = 0 in H^2(G;Z/2)?
|All times are GMT -5. The time now is 02:28 PM.|
Powered by vBulletin Copyright ©2000 - 2013, Jelsoft Enterprises Ltd.
© 2012 Physics Forums