prove jacobian matrix is identity of matrix of order 3
If f(x,y,z) = xi + yj +zk, prove that Jacobian matrix Df(x,y,z) is the identity matrix of order 3.
Because the D operator is linear, D1f(x,y,z) = i, D2f(x,y,z) = k, D3f(x,y,z) = k There is clearly a relationship between this and some sort of identity, but I'm not sure how to state it, and I don't understand the order of linear transformations. Could someone help me? 
Re: prove jacobian matrix is identity of matrix of order 3
*typo on D2f(x,y,z) = j
actually I was just rethinking about the problem. could Df(x,y,z) = ((1,0,0),(0,1,0),(0,0,1)), which becomes an identity matrix, and the order of 3 refers to 3x3 matrix? 
Re: prove jacobian matrix is identity of matrix of order 3
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Re: prove jacobian matrix is identity of matrix of order 3
awesome. thanks!

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