how to get tis relation any hints:

Re: how to get tis relation any hints:
Assuming those vectors add to zero, just add the horizontal components.

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Do you know how to find components of a vector? Read this: Resolving a Vector Into Components 
Re: how to get tis relation any hints:
The statement [itex]T_1= T_2+ T3cos(\theta)[/itex] is only true if, "T_{1}", "T_{2}", and "T_{3}" are the lengths of the vectors shown and the horizontal components sum to 0. (If both T_{1} and T_{2} are horizontal and T_{3} isn't, as shown, the vectors them selves cannot sum to 0.)
Since T_{1} and T_{2} are both horizontal, you need to look at the horizontal component of T_{3}. Drop a perpendicular from the tip of T_{3} to the horizontal. You get a right triangle with angle [itex]\theta[/itex] and hypotenuse of length T_{3}. The horizontal component of T_{3}, T[sub]x[sub] then satisifies [itex]cos(\theta)= T_x/T_3[/itex] so [itex]T_x= T_3 cos(\theta)[/itex]. 
Re: how to get tis relation any hints:
http://i274.photobucket.com/albums/j...phyiscs/t2.jpg
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