Volume by cross-section: ellipse and equilateral triangle cross sections??
1. The problem statement, all variables and given/known data
The base of a solid is the region bounded by the ellipse 4x^2+9y^2=36. Find the volume of the solid given that cross sections perpendicular to the x-axis are:
a) equilateral triangles
2. Relevant equations
3. The attempt at a solution
So I'm not really sure how ellipses work.. how can I sketch this ellipse?
Beyond that.. I try to calculate the area of the triangle and then integrate in terms of y so the base is changing according to the ellipse curve.
I write the ellipse as:
y = +/-sqrt((-4/9)x^2 + 4)
So the base of the triangle is 2(sqrt((-4/9)x^2 + 4))
And has that as the length on all side since it is equilateral.
Then I try to find the height using Pythagoras and get
h = +/-sqrt((-4/3)x^2 + 12)
Then now I have the area of the triangle as (1/2)bh, which is =
A = (1/2)(2(sqrt((-4/9)x^2 + 4)))(sqrt((-4/3)x^2 + 12))
Then I can integrate in terms of x.. does that look correct so far?
|All times are GMT -5. The time now is 04:48 AM.|
Powered by vBulletin Copyright ©2000 - 2013, Jelsoft Enterprises Ltd.
© 2013 Physics Forums