Cartesian equation of a plane perpendicular to anothe plane with certain intercepts
1. The problem statement, all variables and given/known data
Determine the Cartesian equation of the plane that is perpendicular to the yzplane and has yintercept 4 and zintercept 2. 2. Relevant equations ? 3. The attempt at a solution I'm pretty sure that the normal to the plane I want to find would be (0,1,1). A yintercept would go through (0,y,0) and a zintercept would go through or be (0,0,z). How do I make an equation with a y and z intercept at 4 and 2 respectively? 
Re: Cartesian equation of a plane perpendicular to anothe plane with certain intercep
Quote:
If you're not already doing so, draw a sketch using a threedimensional coordinate system. It will help you get your head around these kinds of problems. 
Re: Cartesian equation of a plane perpendicular to anothe plane with certain intercep
My teacher said to forget about learning how to sketch, so that's out. Is the normal to the plane (1,0,0) then? So (0,4,0) and (0,0,2) are both on the plane. How would I stick those points on a plane with a Cartesian equation of x=0, then? I need to get a Dvalue, which I can get from points, I know, but when the equation is 1x + 0y + 0z + D, would the intercepts kind of not really matter? The Dvalue would be 0, so the equation would be x=0, right? Or am I wrong about the normal again? Or am I supposed to be looking for the direction vector formed by the two intercepts and use that as my normal?

All times are GMT 5. The time now is 07:26 PM. 
Powered by vBulletin Copyright ©2000  2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums