Oxygen Bond Angle Increase: Reason Behind Increase?

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Discussion Overview

The discussion revolves around the increase in bond angles in compounds of the oxygen family as one moves down the group, specifically comparing H2O, H2S, and H2Se. Participants explore the reasons behind this trend, considering factors such as electronegativity and steric effects.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the increase in bond angle is due to oxygen's higher electronegativity, which causes its lone pairs to be held more tightly, reducing their ability to repel bond pairs with hydrogen.
  • Another participant agrees with the electronegativity argument, stating that as oxygen pulls the bond pairs closer, the repulsion between them increases, leading to a larger bond angle.
  • A different viewpoint introduces the concept of steric effects, noting that the ionic radii of the anions (O(2-) < S(2-) < Se(2-)) influence the bond angle due to the proximity of bond pairs in H2O.
  • One participant emphasizes that while electronegativity decreases down the group, leading to weaker attraction for bonded pairs and decreased electron pair repulsion, the size of the central atom also plays a role, though it is less significant than electronegativity.

Areas of Agreement / Disagreement

Participants express differing views on the primary reasons for the increase in bond angles, with some supporting the electronegativity explanation while others highlight steric effects. No consensus is reached on which factor is more dominant.

Contextual Notes

Participants mention various assumptions regarding electronegativity and ionic radii, but these points remain unresolved and depend on specific definitions and contexts.

HIGHLYTOXIC
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If we take a look on the following compounds in the Oxygen family, the bond angle increases as we go down the group as :

H2O > H2S > H2Se

Whats the reason for this increase?

Is that :

1. Oxygen is more electronegative than the two, so it holds its lone pairs more tightly than the other two..Thus, the lone pairs are tightly bound to the oxygen atom, not free to wander about & repel the bond pair with hydrogen, therefore making the angle much larger.

OR​

2. Oxygen being more electronegative, pulls the two bond pairs close to itself, as the bond pairs move closer, the distance btw them decreases & this makes the bond angle larger.

Which of the above reason is right?

Thanks!
 
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oxygen being electro negative..it holds the two bond pairs more tightly than the other other elements.. as the are pulled towards oxygen ,repulsion between these pairs increases.hance they posses a larger bond angle

the second one is correct
 
I believe there is also a steric effect coming from the size of the anion. Comparing ionic radii, O(2-) < S(2-) < Se(2-). So the bond pairs (H-atoms) are closer to each other in H20 giving rise to stronger repulsion, and hence greater bond angle.
 
The primary reason is that electronegativity decreases down the group as you go from O to S to Se. So the attraction for the two bonded pairs of electrons decreases as well. As a result, the electron pairs are not pulled as strongly by the central atom as you go down the group causing and therefore, electron pair repulsion decreases, decreasing the bond angle.

The electronegativity reason is more pronounced than the effect of increasing size of the central atom, as we were taught in class. However, size does have some role to play so we must not rule it out of our thinking completely. The second one is therefore correct and holds in general for most such bond angle predictions Highlytoxic.

Hope that helps,

Cheers
Vivek
 

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