How to prove an interval is open?
1. The problem statement, all variables and given/known data
I can repeat the proof, but then I won't understand it.
How do I prove that an open interval like (1,2) is open?
2. Relevant equations
I know it has something to do with neighbourhood with a given epsilon, but I dont really get what a neighbourhood is, I have a maybe rough picture of it but not sufficient enough
it'd be nice if you could explain in some sort of analogy or plain english :)
3. The attempt at a solution
let x be in (1,2)
then neighbouthood will be inside (1,2)
and I just get lost from there
Re: How to prove an interval is open?
Here's some plain English:
A set is open if for any point inside the set, you can always find more points between here and the edge. So (1,2) is open because if you are at 1.99, you can find 1.999, and so on. But [1,2] is closed because if you are at 2, then there are no more points between here and the edge.
|All times are GMT -5. The time now is 07:36 AM.|
Powered by vBulletin Copyright ©2000 - 2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums