How Does Temperature Affect Balloon Volume According to Charles' Law?

  • Thread starter Thread starter bigDee
  • Start date Start date
  • Tags Tags
    Chemistry
Click For Summary
SUMMARY

This discussion centers on the application of Charles' Law to determine the volume of a balloon when subjected to a temperature change. The initial conditions include a balloon at 22° C with a volume of 0.5 liters, placed in a refrigerator at 4° C. The correct approach involves converting Celsius to Kelvin using the formula "C° + 273.15" and applying Charles' Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, provided pressure remains constant. The user initially miscalculated the volume but later corrected their approach by properly applying Charles' Law.

PREREQUISITES
  • Understanding of Charles' Law and its application in gas behavior
  • Knowledge of temperature conversion from Celsius to Kelvin
  • Familiarity with the Ideal Gas Law
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the Ideal Gas Law and its implications for gas behavior
  • Practice temperature conversions between Celsius and Kelvin
  • Explore real-world applications of Charles' Law in various scientific contexts
  • Work through additional problems involving gas volume and temperature changes
USEFUL FOR

Students studying physics or chemistry, educators teaching gas laws, and anyone interested in understanding the principles of thermodynamics and gas behavior.

bigDee
Messages
2
Reaction score
0
The temperature inside my refrigerator is about 4° celsius. If I place a balloon in my fridge that initially had a temperature of 22° C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled in my refrigerator?

Ok now the problem I have here is that the teacher says to always convert C to kelvin (i think that's it). And the formula for that is "C° + 273.15". So well uhhh I don't know what my problem is but I have a feeling I didnt do this right. I got V = .53247 liters. Is that right?

What I did was multiplied 295.15 (which is 22° C in kelvin) by 0.5 liters. I got 147.575. So I divided 147.575 by 277.15 (which is 4° C in kelvin) which got me .53247 liters.

Please help cause I just got to know how to do this so I can do the other 20 or so problems.
 
Physics news on Phys.org
So, you're showing that the balloon expands as it gets colder? I don't think so.

How you work this rather depends on what you were taught. You can do it with the Ideal Gas Law (assuming pressure remains constant), or you could try Charles' Law:

http://members.aol.com/profchm/charles.html
 
Last edited by a moderator:
Yeah my bad I got it working now. I forgot to use Charles law lol.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
5K
Replies
24
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
5
Views
3K
Replies
2
Views
2K
Replies
4
Views
5K
Replies
11
Views
5K
Replies
17
Views
4K