Why Am I Struggling with Projectile Motion Problems in Physics?

  • Thread starter Thread starter HurricaneH
  • Start date Start date
  • Tags Tags
    Hose Physics
Click For Summary
SUMMARY

This discussion focuses on solving projectile motion problems in physics, specifically involving a firefighter's hose and a rifle's bullet trajectory. The first problem involves calculating the height at which water hits a building 50 meters away when directed at a 30-degree angle with an initial speed of 40 m/s. The correct approach requires using the projectile motion equations rather than simple trigonometry. The second problem addresses the trajectory of a bullet aimed horizontally at a target 200 meters away with an initial speed of 500 m/s, necessitating the use of kinematic equations to determine the bullet's drop and the required angle for accurate targeting.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic trigonometry skills
  • Knowledge of gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Study the derivation and application of the projectile motion equations
  • Learn how to solve quadratic equations in physics contexts
  • Explore the effects of air resistance on projectile trajectories
  • Practice additional problems involving angles and distances in projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone seeking to improve their problem-solving skills in kinematics.

HurricaneH
Messages
10
Reaction score
0
Help:(

1) A firefighter, 50m away froma building, directs a hose at an angle of 30*, if the initial speed of the stream is 40m/s, what height does it hit the building?

i'm guessing i make a triangle and solve for h

tan30= h/50, solve for h, i get 28 m

...but it's not the right answer, what am i doing wrong?

2) A rifle is aimed horizontally at the center of a large target 200m away. The initial speed of the bullet is 500m/s. A) Where does the bullet strike the target? B) What angle above the line of sight should the rifle be to hit the target?

I don't know what equation to use:(
 
Physics news on Phys.org
1) Why do you think the water will flow as a STRAIGHT line??
It does not; it follows the parabola given by ordinary projectile motion
2)Similarly here
3)Don't double post
 
ugh, should have been obvious:(

so i would have to find t, using the equation X=Xxo+Voxt+1/2axt*2

50=40t + 4.9t^2

solve for t using the quadratic equation

then plug in t into Y=Yyo+ Voyt+1/2ayt^2

Yyo= o
Voy=20
a= 9.81
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
40
Views
4K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
5K
  • · Replies 4 ·
Replies
4
Views
7K