Solving Elastic HW Problem: Speed of Bullet Impacting Block

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Homework Help Overview

The problem involves a bullet impacting a block and compressing a spring, focusing on the principles of momentum and energy conservation. It is situated within the context of mechanics, specifically dealing with collisions and spring dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum and energy, with some suggesting a two-step collision approach. Questions arise regarding the role of the spring and how to handle the lack of initial velocities.

Discussion Status

Some guidance has been offered regarding the use of conservation laws, with participants exploring different interpretations of the problem. There is a mix of confusion and attempts to clarify the steps involved in solving the problem.

Contextual Notes

Participants express uncertainty about the implications of the spring's compression and the initial conditions of the system. The problem's complexity is compounded by the lack of explicit velocities provided in the question.

doxigywlz
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Okay--- Here's the question:

A 12.0-g bullet is fired horizontally into a 100-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 150 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 80.0cm, what was the speed of the bullet at impact with the block?

I understand that this is an elastic question and I'll need to use conservation of momentum and probably conservation of kinetic energy... But the whole spring thing throws me off? What does it mean? And how do I go about solving this problem when NO velocities are given? Accept for the block being initially at rest...

I'm confused. Help. Please Help.
 
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Try treating this as two colisions:

First the bullet has a (perfectly inelastic) colision with the block.
Then the block hits the spring conserving energy.
 
Okay, that's easy to picture... but then, isn't m1v1=m2v2? (cons. of momentum) do you solve for one of these velocities and then plug it into the cons of kinetic energy equation?
 
ANYBODY out there to help?
 
I am still confused with this problem, 2 days later.. so if anyone is willing to help, I'm willing to be helped!
 
Use conservation of mechanical energy and conservation of momentum.

Conservation of momentum

[tex]m_{bullet}v_{bullet} = (m_{bullet} + m_{block})v_{both}[/tex]

Conservation of Mechanical energy

[tex]\frac{1}{2}(m_{bullet} + m_{block})v_{both}^{2} = \frac{1}{2}kx_{max}^{2}[/tex]


do you need more help than that?
 
Last edited:
no, thank you. i don't know how you know all this stuff but i wish i had your brain
 
doxigywlz said:
no, thank you. i don't know how you know all this stuff but i wish i had your brain

Well if you really want to know... Being patient, practicing a lot!, making sure you understand the concepts and the LIMITATIONS! of the theories. :smile:
 
the final answer for Vi=273.28 m/s
 

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