Coefficient of Friction between slide/girl
1. The problem statement, all variables and given/known data
A 36kg girl slides down a slide that is 4.5m long. At the bottom of slide she is moving at 3 m/sec. If slide is inclined at 35 degrees find the coefficient of friction between slide and girl. 2. Relevant equations Ff = μ*Force normal Total energy = KE + PE KE = 1/2 mv^2 PE = mgh Total energy = F cosθ 3. The attempt at a solution KE = 162 using above formula, PE = 911.15. Total energy = 1073.15 F = 1310.32 using the cosθ formula. And that is where I am stuck  is the F the normal force or the Ff (from friction) how would I solve for the coefficient from this point? And have I even approached it in the right way so far? 
Re: Coefficient of Friction between slide/girl
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Secondly; why did you add KE and PE together? Surely we had pE at the top and KE at the bottom, but never both at the same time [perhaps half and half on the way down, but you were considering the top and the bottom, I hope] You said, Total energy = KE + PE At the top that would be Total energy = 0 + PE At the bottom that would be Total energy = KE + 0 And those two totals are different, due to the friction. Edit: Total energy = F cosθ makes you group of formulas look like a grabbag of possibilities, rather than a reasoned list of what actually applies. 
Re: Coefficient of Friction between slide/girl
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