If u is a nonnegative, additive function, then u is countably subadditive
I'm trying to prove the following:
http://i3.photobucket.com/albums/y89...ale/fsdfsd.png I ran into a roadblock at the end. I can't use the assumption that [itex]\mu[\itex] is additive because we don't know that [itex](\cup{A_k}) \cap A_{j + 1} = \emptyset[\itex]. We do know that [itex]\mu(\cup_{k=1}^jA_k) + \mu(A_{j + 1} \leq \sum_{k=1}^{j+1}\mu(A_k)[\itex]. 
Re: If u is a nonnegative, additive function, then u is countably subadditive
You don't really need to worry about the intersection stuff. It's enough to note that a nonnegative additive function will be (finitely) subadditive.

All times are GMT 5. The time now is 09:14 AM. 
Powered by vBulletin Copyright ©2000  2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums