Bohr model of the atom
Eisberg and Resnick says that the condition for stability of the atom is:
What I fail to understand is why the Z isnt square too. I mean surely you have Z electrons interacting with Z protons which which would surely give q1q2=(Ze)(-Ze)=-Z2e2?
What am I missing?
Re: Bohr model of the atom
No. They are dealing with a one electron atom. You might say: then it's hydrogen, so why not put Z = 1? They leave Z open so the same treatment will do for, an He+ ion and so on.
Incidentally the equation you give isn't really the condition for stability. It is the classical F = ma equation for circular orbits. The stability condition is Bohr's condition: mvr = n[itex]\hbar[/itex].
|All times are GMT -5. The time now is 04:14 AM.|
Powered by vBulletin Copyright ©2000 - 2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums