(1.0 / 2) process repeated 5 times; what is the algrabraic formula?
1 / 2 = 0.5
0.5 / 2 = 0.25 0.25 / 2 = 0.125 0.125 / 2 = 0.0625 0.0625 / 2 = 0.03125 What is the algebraic formula for this? 
Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
[itex]\frac{1}{2^5}[/itex]

Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
This is a new one;
64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1 1 / 2 = 0.5 0.5 / 2 = 0.25 0.25 / 2 = 0.125 0.125 / 2 = 0.0625 0.0625 / 2 = 0.03125 [itex]\frac{64}{2^{10}}[/itex] 
Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Thanks.

Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
That should actually be [itex]\frac{64}{2^{11}}[/itex].
Edit: Enclose your "10" in { } to make it appear correctly. 
Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Your right, I added one too many and thought there was only ten.

Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Thanks for the editing tip.

Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Quote:
[tex]\frac{1}{2^n}[/tex] is a formula. 
Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Quote:

Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Quote:
[tex]\frac{64}{2^{10}}=\frac{2^5}{2^{10}}[/tex] And if you remember the rule of indices, [tex]\frac{2^a}{2^b}=2^{ab}[/tex] so [tex]\frac{2^5}{2^{10}}=2^{510}=2^{5}=\frac{1}{2^5}[/tex] As we got in your first question. 
Re: (1.0 / 2) process repeated 5 times; what is the algrabraic formula?
The formula (not sure if this is considered algebraic) or notation for a product series in the original example would be:
[tex]\prod_{i=1}^5 \ \frac{1}{2} [/tex] 
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