Kinematic Problem: Solve Traffic Light Stop Distance

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Homework Help Overview

The problem involves a motorist approaching a traffic light and calculating the stopping distance after a reaction time, with specific parameters regarding speed, distance, and deceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of kinematic equations and the implications of reaction time and deceleration on stopping distance. Questions about the meaning of acceleration in the context of the problem are raised.

Discussion Status

Some participants have provided guidance on using kinematic equations, while others are seeking clarification on specific concepts related to acceleration and deceleration. There is an ongoing exploration of the problem without a clear consensus on the approach.

Contextual Notes

Participants note the importance of understanding the parameters given, such as the motorist's speed, reaction time, and maximum deceleration, which may influence the calculations.

ireneooi
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Hi,really need help with this question.
A motorist traveling at 13 m/s aprroaches traffic lights which turn red when he is 25m away from the stop line.His reaction time(i.e. the interval between seeing the red light and applying the brakes)is 0.7s and the condition of the road and his tyres is such that the car cannot slow down at a rate of more than 4.5 ms-2.If he brakes fully,how far from the stop line will he stop,and on which side of it?

Thanks in advance!
 
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Please show us some effort from u! It is not that we cannot give you help.
 
use the very simple kinematics equations available. Manipulate them to et an answer. If you have a more specific probem in this question, please state it. Nobody will solve your problem for you.

[tex]V^2 = {V_o}^2 + 2ad[/tex]
[tex]d = V_o t + \frac{1}{2} at^2[/tex]
[tex]V = \frac{d}{t}[/tex]

Regards,

Nenad
 
Oh,sorry,I actually just have one problem,which is the acceleration part of the question.Can anyone just explain what it means?Thanks.
 
It's a deceleration.With constant acceleration [itex]a=-4.5ms^{-2}[/itex]...

Daniel.
 

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