Proving Rotational K.E. Formula?
The total kinetic energy (as viewed from one inertial frame) of a free, rigid body is the sum of all the infinitesimal kinetic energies of the components that comprise the body.
How do we prove that for a rotating body [tex]E_k=\frac{1}{2}\left(M_{T} v_{c}^{2} + I_{c} ω^{2}\right)[/tex] 
Re: Proving Rotational K.E. Formula?
Where M_{T} stands for the total mass of all the infinitesmal components combined.

Re: Proving Rotational K.E. Formula?
Integrate ##\int \frac{1}{2}v^2 \rho dV## (in other words, kinetic energy = 1/2m^2 for all infinitesimal m) and split v into components from translation and rotation and you will get the correct result.

All times are GMT 5. The time now is 07:40 AM. 
Powered by vBulletin Copyright ©2000  2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums