Pressure Difference in a 2-m Deep Swimming Pool

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    Thermodynamics
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Homework Help Overview

The discussion revolves around calculating the pressure difference in a 2-meter deep swimming pool, focusing on hydrostatic pressure principles.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the pressure difference using a formula involving density, height, and gravity. Some participants question the terminology used, with one suggesting it relates to Pascal's law.

Discussion Status

The discussion includes confirmation of the original poster's calculation, but there is also a divergence in terminology and understanding of the principles involved. No explicit consensus has been reached regarding the terminology or the application of Bernoulli's equation versus Pascal's law.

Contextual Notes

One participant notes a lack of familiarity with hydrodynamics due to missed classes, which may affect their contributions to the discussion.

Naeem
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Q. Consider a 2-m deep swimming pool. The pressure difference between the top and bottom of the pool is :

Here is what I did:

Pdiff. = Denisty(h20) * height * gravity

Pdiff = 1000* 2m * 9.81 = 19.6 kPa

Is this correct.

Plz help
 
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You are correct. It's just Bernoulli's equation.

- Warren
 
Sure.But in this hydrostatic case,i think it's called Pascal's law...(not sure,been missing classes on hydrodynamics :wink:)...

Daniel.
 
Meh.

-Warren
 

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