Find the gradient of f(x,y). f(x,y)=(x^2)e^2y
Here's the problem. Find the gradient of f(x,y). f(x,y)=(x^2)e^2y.
I don't have the solution to this and I need to know if I got the right gradient (I have more problems that depend on this gradient, points on it). I ended up getting, gradient f=<2xe^2y, 2x2e^2y>. I don't think it's right, but can someone help me out here? 
No.
grad f= f_{x}(x,y)i + f_{y}(x,y)j f_{x}(x,y)=(2x)e^{2y} f_{y}(x,y)=(2*2x)e^{2y} 
Sorry, Stephen, you have f_{y} wrong.
The derivative of e^{2y} with respect to y is 2 e^{2y} The other factor, x^{2} is independent of y so treat it like a constant f_{y}= (x^{2})(2e^{2y})= 2x^{2}e^{2y}. The gradient of 2xe^{2y} is the vector <2x e^{2y}, 4xe^{2y}>. What ffrpg wrote: f=<2x^e2y, 2x2e^2y> may be typos or just carelessness: x^e2y doesn't make much sense and in "2x2..." you MEANT (2x) times (2), not 2x subtract 2... 
Ah yes. Where is my head?

All times are GMT 5. The time now is 02:20 AM. 
Powered by vBulletin Copyright ©2000  2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums