Find the gradient of f(x,y). f(x,y)=(x^2)e^2y
Here's the problem. Find the gradient of f(x,y). f(x,y)=(x^2)e^2y.
I don't have the solution to this and I need to know if I got the right gradient (I have more problems that depend on this gradient, points on it). I ended up getting, gradient f=<2xe^2y, 2x2e^2y>. I don't think it's right, but can someone help me out here? 
No.
grad f= f_{x}(x,y)i + f_{y}(x,y)j f_{x}(x,y)=(2x)e^{2y} f_{y}(x,y)=(2*2x)e^{2y} 
Sorry, Stephen, you have f_{y} wrong.
The derivative of e^{2y} with respect to y is 2 e^{2y} The other factor, x^{2} is independent of y so treat it like a constant f_{y}= (x^{2})(2e^{2y})= 2x^{2}e^{2y}. The gradient of 2xe^{2y} is the vector <2x e^{2y}, 4xe^{2y}>. What ffrpg wrote: f=<2x^e2y, 2x2e^2y> may be typos or just carelessness: x^e2y doesn't make much sense and in "2x2..." you MEANT (2x) times (2), not 2x subtract 2... 
Ah yes. Where is my head?

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