What is the height of the wine column in Pascal's barometer?

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Homework Help Overview

The discussion revolves around calculating the height of a wine column in a barometer, specifically using a red Bordeaux wine with a given density. The context involves comparing this setup to a traditional mercury barometer and understanding the implications of using a different liquid.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Pascal's formula for pressure and the implications of using wine instead of mercury. Questions arise about the correct interpretation of pressure in the equation and the expected height of the wine column under normal atmospheric conditions.

Discussion Status

The discussion includes attempts to clarify the pressure terms in the equation and the relationship between atmospheric pressure and the liquid column. There are differing interpretations regarding the expected height of the column and the effects of using a different liquid, with some participants providing guidance on the setup.

Contextual Notes

Participants note the density of the wine and its implications for the calculations, while also referencing the traditional mercury barometer for comparison. There is an acknowledgment of the need to consider the vacuum above the liquid column in the context of the experiment.

imnotsmart
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Blaise Pascal duplicated Torricelli's barometer using a red Bordeaux win, of density 984 kg/m^3, as the working liquid. What was the height of the wine column for normal atmospheric pressure? Would you expect the vacuum above the column to be as good as for mercury?
 
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The first question is trivial.Use Pascal's formula.

Daniel.
 
So that is P=Po+(row)(g)(h)
P=1.013*10^5+(984kg/m^3)(9.8)(h)...is this correct?
 
No.It should be vacuum on top of the wine...

Daniel.
 
I don't understand what you are saying.
 
I'm saying that the experiment should be the same as in the case of Torricelli,but the length of the tube be >14 times bigger.

Daniel.
 
imnotsmart said:
So that is P=Po+(row)(g)(h)
P=1.013*10^5+(984kg/m^3)(9.8)(h)...is this correct?
What is P in this equation ?
 
P is suppose to be the pressure, but I am not sure what that is...I don't get this problem at all.
 
There is no other P involved.

On one side of the column, you have atmospheric pressure (Po). On the other side, you have vacuum (P=0). So, the force due to the liquid column must balance the force due to the atmosphere.
 
  • #10
So is the answer -10.5?
 
  • #11
It should be a plus.But yeah,it's good.

Daniel.
 
  • #12
Is it good for mercury?
 
  • #13
What?That #?Nope,it's computed for wine.

Daniel.
 
  • #14
thanks for your help buddy...
 
  • #15
Remember, you used the density of wine, not the density of mercury.
 

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