Transition Energy in ev's Emitted wavelengths in m

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Homework Help Overview

The discussion revolves around calculating the wavelength of emitted light during an electron transition in a hydrogen atom, specifically from energy level 2 to level 1. Participants are exploring the relationship between energy, frequency, and wavelength in the context of quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula E=hf and its relation to frequency and wavelength. There are attempts to calculate energy differences between electron states and to derive wavelength from frequency. Questions arise about the correct application of constants and the relationships between energy levels.

Discussion Status

Multiple interpretations and calculations are being explored, with some participants providing guidance on using Planck's constant in different units. There is acknowledgment of errors in calculations, and some participants are seeking clarification on energy levels and their relationships.

Contextual Notes

Participants mention the need for specific energy values for different levels in hydrogen and discuss the implications of using different units (eV vs. Joules) in their calculations. There is an ongoing inquiry into the energy level of higher states beyond the provided values.

whiteshado
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could i get help or a formula for this question please

Use the Energy Levels for Hydrogen to calculate the wavelength corresponding to the following electron transition
Transition Energy in ev's Emitted wavelengths in m
2->1______ ________x10______
 
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Here's a formula you can use after you've discovered how many energy is contained in the photon emited during the transition of the electron

[tex]E=hf[/tex]

where f is the frequency of the photon. How are frequency and wavelength related?
 
taht is the question I am as stumped as you are tahts all the info i have i had taht equation though it doesn't haev wavelength also how do i find the energy?
 
I don't think quasar is stumped, i think he was asking you a question which has an answer. The energy should be a given, or predicted by the bohr model. Think back to waves what other equation relates wavelength and frequency.
 
well speed of sound divided by wavelength =frequency
 
is taht what you were asking for?
 
A photon travels at the speed of _____
 
hf is the energy of the radiated photons

thats all i got
 
Ok, a photon travels at the speed of light. If its energy is given by hF, then the relationship


c = (Frequency)(Wavelength) should give you its wavelength. All you ahve to do is find the energy drop from 2->1 and solve this equation and plug it into the E = hF one.
 
  • #10
whiteshado said:
well speed of sound divided by wavelength =frequency

This is also true for light. Light is a wave too, and a "photon" is only a fancy name we give to "little chuncks" (quanta!) of light.

So speed of light divided by wavelength =frequency.
 
  • #11
k so correct me if I am wrong 2-1 =-13.6 evs and w =-13.6evs/6.63e-34

?
 
  • #12
whiteshado said:
k so correct me if I am wrong 2-1 =-13.6 evs and w =-13.6evs/6.63e-34

?

-13.6 eV is the energy the electron has when it is in state n=1.

You're looking for the energy it has lost in going from state n=2 to state n=1, hence you want the difference between the energy of n=1 and the energy of n=2:

[tex]\Delta E = E_f - E_i[/tex]
 
  • #13
12.2? is that it? nope it was 10.2
 
Last edited:
  • #14
yeah.

-----------
 
  • #15
hmm i got 1.15e53
10.2/1.6e-19/6.63e-34
its not right thought i think i missed soemthing
wait is this is my freqwuancy correcT?
 
Last edited:
  • #16
1 kg = 1000 grams, so 2.3 kg = 2.3*1000 = 2300 grams.

Same thing here: 1 eV = 1.6*10^19 J, so 12.2 eV = 12.2*1.6*10^-19 J.
 
  • #17
ahhh i devided instead of multiplying
 
  • #18
In problems like this it's easier to use Planck's constant in eV instead of joules:

[tex]\frac {10.2 eV} {4.14 \times 10^{-15} eV \cdot seconds}[/tex]
 
  • #19
jtbell said:
In problems like this it's easier to use Planck's constant in eV instead of joules:

[tex]\frac {10.2 eV} {4.14 \times 10^{-15} eV \cdot seconds}[/tex]
=f=594574507617985878855444072835.38 correct?\
then speed of light/f=w
299 792 458/594574507617985878855444072835.38=5.04e-22

taht still doesn't give me the correct answer the correct answer is 1.22e-7
 
  • #20
Nope.It should be ~2.5 10^{15}Hz...And the wavelength ~1.22 10^{-7}m.

Daniel.
 
  • #21
ahh yes by useing Planck's constant in its original form thanks for the help again guys
 
  • #22
one mroe question on this the energy lvl of 3 in a hydrogen atom is -1.5 and lvl 1 is -13.6
though my graph shows the infinity sign and a 0.0 for where lvl 6 should be could i get the energy lvl of lvl 6 from someone? or how to get it
 
  • #23
U could have used the # given by J.T.I used,made that division correctly and wound up with the correct frequency...

Daniel.
 
  • #24
i did do taht after i posted and tried useing the constant in ev form
 
  • #25
whiteshado said:
one mroe question on this the energy lvl of 3 in a hydrogen atom is -1.5 and lvl 1 is -13.6
though my graph shows the infinity sign and a 0.0 for where lvl 6 should be could i get the energy lvl of lvl 6 from someone? or how to get it
How is [itex]E_n[/itex] related to [itex]E_1 = -13.6~eV[/itex] ?
 
  • #26
Gokul43201 said:
How is [itex]E_n[/itex] related to [itex]E_1 = -13.6~eV[/itex] ?
did i say that?
 
  • #27
No, I am. From E1, you can calculate E2, E3, ..., En, using a simple formula which relates the energy to the shell number (n). What is this formula ?
 

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