Is activation energy dependent?
I think it isn't, but if you rearrange the Arrhenius equation you get:
Ea - activation energy
Ea = RT(lnA - lnk)
so as temperature Ea can change. But I am thinking that k will also change in relation so Ea is constant?
Ea is temp. independent, K will change with a change in T. So if T changes the -lnK factor will change so Ea will always be constant. A classical chemistry experiment at universities is plotting lnK vs. 1/T. The rate of the reaction at different temperatures is recorded in the lab. From the straight line in plot of lnk vs 1/T you can calculate the slope and the slope is equal to Ea/R.
ok thanks very much.
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