Nonconservative Forces (conceptual)

[Blade]

I'm having problems with solving these nonconservative forces problems. The teach keeps pointing to Wnc=(KE+PE)f - (KE+PE)i

As we use this when there is friction present, I'm totally confused on where the frictional or opposing force is involved when solving. I've basically been ignoring the frictional force when solving for instance for vf, or vi, which I'm sure isn't the right way. I don't seem to be able to find an adequate explanation in the AP book or elsewhere.

 

[Blade]

Example: "A 2.1x10^3kg car starts from rest at the top of a 5.0m long driveway that is sloped at 20 degrees with the horizontal. If an average friction force of 4.0x10^3 N impedes the motion, find the speed of the car at the bottom of the driveway."

I know there's no final kinetic force, and no final potential force, so that leaves me Wnc = KEf - PEi

1/2mv^2 - mgh

h=Fsin20 (I think)

1/2mv^2 - mgh

Yeah... not sure what to do at this point, I was thinking F was also the Ff, but I don't think that's right. I think I'm having trouble with, what happened to Wnc.

 

[mani]

The term "opposing force" is confusing.
Consider a horizontal table and a block projected on it with an initial horizontal velocity. No horizontal force other than the force of friction. What is the " opposing force" here?

You may be meaning any force. If that force is a non-conservative force the work done by that will go into Wnc. The work done by the friction force - almost always negative- will of couse go into Wnc

 

[mani]

"I'm having trouble with, what happened to Wnc."


Wnc = KEf - PEi = 1/2 mv^2 - mgh
(h = L sin20, where L the length of the driveway = 5 meters)

Wnc is also = (Friction force x Distance moved in the direction of the force) = (4x 10^3 Newtons)x(-5 meter),as the direction of distance moved, 5 meter, is opposite to that of the force.

1/2 mv^2 - mg(5 Sin20) = (4x 10^3 Newtons)x(-5 meter)
u know m and g. Find v.