How to Determine Final Temperature and Enthalpy Change During Vaporization?

  • Thread starter Thread starter physicsCU
  • Start date Start date
  • Tags Tags
    Thermo
Click For Summary

Homework Help Overview

The discussion revolves around determining the final temperature and enthalpy change during the vaporization of water in a piston-cylinder setup, with specific conditions provided such as volume, temperature, pressure, and mass.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the ideal gas equation and considers using enthalpy change based on mass and specific enthalpy of vaporization. Some participants suggest consulting water tables and Mollier diagrams for accurate enthalpy values, while others question the appropriateness of the initial approach.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on using thermodynamic tables and questioning the assumptions made by the original poster. There is recognition of the need to clarify the physical understanding of the process involved.

Contextual Notes

There is mention of specific values and conditions, including the pressure being held constant during the heating process, which may influence the interpretation of the problem. The original poster acknowledges missing information from their resources, such as pressure tables.

physicsCU
Messages
198
Reaction score
1
OK, I have a piston-cylinder with water.

V = 50L = 0.05 m^3
T = 25 C
P = 300 kPa
m = 49.85 kg
specific volume @ 25 C = 0.001003 m^3/kg

The water is heated to vaporization with pressure held constant. I need to determine the final temperature and the enthalpy change.

I know what the answers need to be (133.55 C and 103,627 kJ). On the temperature, I tried doing T = (PV/mR), using R = 0.4615 (kPa*m^3)/(kg*K), but i didn't get anywhere close.

On the enthalpy change part, I figured using m*h_fg, but that isn't right (I think).

Any ideas? Thanks a lot!
 
Physics news on Phys.org
physicsCU said:
OK, I have a piston-cylinder with water.

V = 50L = 0.05 m^3
T = 25 C
P = 300 kPa
m = 49.85 kg
specific volume @ 25 C = 0.001003 m^3/kg

The water is heated to vaporization with pressure held constant. I need to determine the final temperature and the enthalpy change.

I know what the answers need to be (133.55 C and 103,627 kJ). On the temperature, I tried doing T = (PV/mR), using R = 0.4615 (kPa*m^3)/(kg*K), but i didn't get anywhere close.

On the enthalpy change part, I figured using m*h_fg, but that isn't right (I think).

Any ideas? Thanks a lot!

1) Look at the water tables to see what enthalpy has the initial state,

2)The thermodynamic trajectory is an isobaric one until you have reached a 100% of water vapor inside cylinder. Look at a Mollier diagram or go to tables to localize the enthalpy of water vapor at 300Kpa. Then you have the enthalpy difference.

3) do not use the equation of state as you've done. It shows you didn't understand the problem at all. Imagine it physically: you are heating water to vaporize it with a free piston, do you really think volume is going to remain constant?
 
OK, I got the enthalpy difference, no problems.

I didn't realize my book had a pressure table, I found it there. Duh.

I neglected to mention that I looked at the v_fg values as well, and that didn't work. Sorry about that.

THANKS so much for your help. No wonder you are an engineer guru!
 
physicsCU said:
THANKS so much for your help. No wonder you are an engineer guru!

You're welcome!. Doubtless, there are another people who just wonder why the hell I am the PF eng. gurú.. :smile: To those...maybe they're right. :biggrin:
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
9
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
2K
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K