Checking Distance Travelled by Car: Is 3.2 km Right?

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SUMMARY

The discussion centers on calculating the distance traveled by a car that accelerates uniformly to a speed of 120 km/h over 1.6 minutes and then decelerates uniformly to a stop over the same duration. The user applied the equation x - x0 = 0.5 * a * t² + v0 * t to determine the distance, arriving at a total of 3.2 km. This calculation is confirmed as correct based on the provided parameters of acceleration and deceleration.

PREREQUISITES
  • Understanding of kinematic equations, specifically x - x0 = 0.5 * a * t² + v0 * t
  • Knowledge of uniform acceleration and deceleration concepts
  • Familiarity with converting time units from minutes to seconds
  • Basic grasp of speed and distance relationships
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn about uniform acceleration and its implications in real-world scenarios
  • Explore the conversion of units, particularly time and speed
  • Investigate practical examples of distance calculations in automotive contexts
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding motion and distance calculations in vehicles.

brad sue
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I would like to check something.
A car leaves a city along a straight road and accelerates uniformly for 1.6 min until it reaches a speed of 120km/h. It then deccelerates uniformly until it comes to rest again after 1.6min
what is the distance traveled by the car?

I used the equ. x-xo=.5*a*t2+vo*t
before I found the acceleration..
I found 3.2 km

Is that right?
Thanks
 
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