Balancing Silver(I)Nitrate & Potassium Iodide Reactions

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SUMMARY

The discussion centers on balancing chemical reactions, specifically the reaction between Silver(I) nitrate and Potassium iodide, which produces Silver(I) iodide and Potassium nitrate. The balanced molecular equation is AgNO3 + KI → AgI + KNO3, with the net ionic equation being Ag⁺(aq) + I⁻(aq) → AgI(s). Participants clarified that soluble compounds like Potassium nitrate do not appear in the net ionic equation, while Silver(I) iodide, being insoluble, does. Additionally, the discussion touched on the hydrolysis of Calcium hydroxide in a separate reaction.

PREREQUISITES
  • Understanding of chemical equations and stoichiometry
  • Familiarity with solubility rules for ionic compounds
  • Knowledge of net ionic equations
  • Basic principles of hydrolysis reactions
NEXT STEPS
  • Study the solubility rules for ionic compounds in aqueous solutions
  • Learn how to derive net ionic equations from complete ionic equations
  • Explore the concept of precipitate formation in double displacement reactions
  • Investigate the hydrolysis of various salts and their implications in chemical reactions
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Chemistry students, educators, and anyone interested in mastering chemical reaction balancing and net ionic equations.

Clueless333
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1. Calcium + Water yields calcuim hydroxide + hydrogen
Need balanced and net ionic equation, I got
Ca + 3/2H20 =Ca(OH)2 +H
I can't figure out how to balance it further and I don't know how to get the net equation cause calcuim hydroxide is soluble which means it wouldn't be in the net equation right?

2. Silver(I)nitrate + potassium iodide yields silver(I)iodide + potassium nitrate
I got
AgNO2- + KI = AgI + KNO2-
Ag+ + I- = AgI
Potassium nitrate is soluble so it's not in the net equation but silver iodide is not soluble so it is. Is it balanced ok? Am I right? Heeelllpp!
 
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Clueless333 said:
1. Calcium + Water yields calcuim hydroxide + hydrogen
Need balanced and net ionic equation, I got
Ca + 3/2H20 =Ca(OH)2 +H
I can't figure out how to balance it further and I don't know how to get the net equation cause calcuim hydroxide is soluble which means it wouldn't be in the net equation right?

[tex]\text{Ca}}\left( {{\text{OH}}} \right)_2[/tex] is soluble in water.
Therefore, you will observe hydrolysis, as:
[tex]{\text{H}}_{\text{2}} {\text{O}} \rightleftharpoons {\text{H}}^ + \left( {aq} \right) + {\text{OH}}^ - \left( {aq} \right)[/tex]

*Or you balance it as:
[tex]2{\text{H}}_{\text{2}} {\text{O}} \rightleftharpoons {\text{H}}_{\text{3}} {\text{O}}^{\text{ + }} \left( {aq} \right) + {\text{OH}}^ - \left( {aq} \right)[/tex]

Clueless333 said:
Silver(I)nitrate + potassium iodide yields silver(I)iodide + potassium nitrate .. ..
*Actually, silver(I) nitrate is--> [tex]\text{AgNO} _ 3[/tex] :wink:

You are right, [tex]\text{KNO} _ 3[/tex] and [tex]\text{AgNO} _ 3[/tex] and [tex]{\text{KI}}[/tex] are all obviously soluble. Looking at your chemicals, you will observe [tex]{\text{AgI}}[/tex] precipitate. Therefore, the net ionic reaction equation will omit the potassium cations and the nitrate anions:

[tex]{\text{Ag}}^ + \left( {aq} \right) + {\text{I}}^ - \left( {aq} \right) \rightleftharpoons {\text{AgI}}\left( s \right)[/tex]

Remember those common solubility rules. They can help greatly :smile:
 
Last edited:
ok, I understand how to work out soluble and nonsoluble compounds but I do not know how to write Net Ionic Equations. So if I had:

BaCl2(aq) + 2AgNO3(aq) -->Ba(NO3)2(aq)+2AgCl(s)

Would the Net Ionic equation be:
a) 2Ag+(aq) + 2Cl-(aq) -->2Ag+Cl-(s)

or
b) Ag+(aq) + Cl-(aq) --> Ag+Cl-(s)

or
c) 2Ag+(aq) + Cl2-(aq) --> 2Ag+Cl-(s)

My current guess would be (c)
 

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