How Does Catching a Ball Illustrate the Conservation of Momentum?

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SUMMARY

The discussion centers on the conservation of momentum illustrated by the scenario of catching a ball. When a ball with a mass of 0.400 kg is thrown at a velocity of 10.0 m/s and caught by a person weighing 65.5 kg, the combined velocity post-catch is calculated using the formula (0.400 kg * 10.0 m/s) = (65.9 kg * v_2), resulting in a final velocity of approximately 0.0607 m/s. This calculation assumes no external forces are acting on the system, confirming the principle of momentum conservation.

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Somebody throws me a ball with mass .400 [tex]kg[/tex] at velocity 10.0 [tex]m/s[/tex]. My mass is 65.5 [tex]kg[/tex].

1. If I catch the ball, with what speed do the ball and I move afterwards?

Shouldn't the answer be [tex](.400)(10.0=(65.9)(v_2)[/tex], where [tex]v_2=.0607[/tex][tex]m/s[/tex]?
 
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That's correct. (Assuming no other forces act on you.)
 

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