Solving Partial Derivative Equation: Finding Error & Fixing It

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SUMMARY

The discussion focuses on solving the partial derivative equation for the function {\Psi} = Ae^{-a(bx-ct)^2}. The user expands the equation incorrectly, leading to an erroneous derivative calculation. The correct derivative should yield (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}, indicating a mistake in the expansion of (bx-ct)^2. The user seeks clarification on the error and guidance on proper expansion techniques.

PREREQUISITES
  • Understanding of partial derivatives and notation
  • Familiarity with exponential functions and their properties
  • Knowledge of algebraic expansion techniques
  • Basic concepts of calculus, particularly in relation to multivariable functions
NEXT STEPS
  • Review the process of expanding binomials, specifically (bx-ct)^2
  • Study the rules of partial differentiation for multivariable functions
  • Practice deriving exponential functions with multiple variables
  • Explore common errors in calculus and how to avoid them
USEFUL FOR

Students and professionals in mathematics, physics, or engineering who are working with partial differential equations and need to enhance their understanding of derivative calculations.

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I'm trying to figure out this equation.

[tex] {\Psi} = Ae^{-a(bx-ct)^2}[/tex]

I've expanded this to

[tex] {\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}[/tex]

When I try to find the derivative I get this

[tex] \left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }<br /> <br /> \pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}[/tex]

I should get this instead

[tex] \left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }<br /> <br /> \pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}[/tex]

Can anyone tell me where my error is and how I can fix it?
 
Last edited:
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Try again in expanding
[tex](bx-ct)^2[/tex]
 

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