1D wave PDE with extended periodic IC

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SUMMARY

The discussion centers on solving the 1D wave equation using the formula u(x, t) = 1/2 [ f(x + ct) + f(x - ct) ] + 1 / (2c) Integral( g(s), wrt s, from x-ct to x+ct). The specific case involves L = 1, c = 1, f(x) = 0, and g(x) = x(1 - x). To apply this formula, the initial position f(x) and initial velocity g(x) must be extended to periodic functions, determined by the integer n such that nL <= x < (n+1)L. The discussion also addresses the method of extending g(x) based on whether n is even or odd.

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eckiller
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I have formula for 1D wave equation:

(*) u(x, t) = 1/2 [ f(x + ct) + f(x - ct) ] + 1 / (2c) Integral( g(s), wrt
s, from x-ct to x+ct )

I am trying to find u(1/2, 3/2) when L = 1, c = 1, f(x) = 0, g(x) = x(1 -
x).

However, for (*) to work, the initial position f(x) and initial velocity
g(x) must be extended to periodic functions.

"To determine f(x) and g(x) we need only find the integer n s.t. nL <= x <
(n+1)L, [where L is the right boundary length from the origin]."

It then gives the ways of extending if n is even or odd. If even, gx) =
g(x - nL). If odd, g(x) = -g((n+1)L - x).

How do I determine what n is for g to extend it correctly?

I need to figure out nL <= x < (n+1)L, yes. But what is x for g? For
f(x+ct) it is clear. But g is in the integral...
 
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