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jaredmt
#3
Jul7-08, 02:21 PM
P: 122
i dont know how to type the integration symbols

the double integral was ||Rx X Ry||
where x = x, y = y, z = x^2 + y^2

so basically (skipping some steps) the integral becomes: (1 + 4x^2 + 4y^2)^.5
which becomes: r(1 + 4r^2)^.5 when put in polar form
and like i said, i tried 0<feta<2pi and 0<r<3

i got like pi/6 * some quantity. but its supposed to be 4pi