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Apr13-04, 12:21 AM
P: 46
How can I show that if
[tex]\frac{a}{a^2-2b^2},\frac{b}{a^2-2b^2}\in \mathbb{Z}[/tex]

then [tex] a^2-2b^2=\pm 1[/tex]?
If you care to see the whole problem, you can find it here:
It's #4 part c.

BTW, why is the significance of this "norm map"? I tried to google it for fun, but couldn't find much.
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