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Oct18-08, 12:49 PM
Cyrus's Avatar
P: 4,777
I see. I want the more general case, where the upper and lower limits are +/- infinity. So then, the last case holds just as you stated but a is -inft instead of a finite value.

When it comes to the last integral, it would have to be split up as:

[tex]\int^\infty_{t+} + \int^t_{-\infty} [/tex]

Where the second integral is *just after* t, right?

Otherwise, if it were split at the value of time t, you would get 2x(t) when you did the integral piecewise.